Using JBoss 3.2.3, I'm trying to implement a finder method on an entity using a wildcard and the WHERE ... LIKE construct.
My EJB-QL is as follows.
SELECT OBJECT(o) FROM BicBankEntity AS o
WHERE o.cInstCouLoc like ?1
This fails with the following error when installing the EJB.
[ObjectName: jboss.j2ee:jndiName=IntraInstitutionVolumeEntityRemote,service=EJB
state: FAILED
I Depend On:
Depends On Me: org.jboss.deployment.DeploymentException: Error compiling EJB-QL
statement 'SELECT OBJECT(o) FROM BicBankEntity AS o WHERE o.cInstCouLoc like ?1
'; - nested throwable: (org.jboss.ejb.plugins.cmp.ejbql.ParseException: Encounte
red "1" at line 1, column 67.
Was expecting:
<STRING_LITERAL> ...
)]
I have tried using the following EJB-QL
SELECT OBJECT(o) FROM BicBankEntity AS o
WHERE o.cInstCouLoc like '?1%'
but the SQL generated merely tries to match the column with the literal '?1%'.
How should the WHERE ... LIKE clause be specified?, is this a bug in 3.2.3.
Any help would be appreciated.
Thanks in advance
