ejbql query-path of derived entity

[gnulp]

I tried to drill down the problem to following simple example:

Address has a simple relation to Person which is derived from Employee ...

@javax.persistence.Entity
public class Address {
 String street;
 Long id;
 Person person;
 public String getStreet() {
 return street;
 }
 public void setStreet(String value) {
 street = value;
 }
 @javax.persistence.Id
 public Long getId() {
 return id;
 }
 @javax.persistence.ManyToOne
 public Person getPerson() {
 return this.person;
 }
 public void setPerson(Person person) {
 this.person = person;
 }
}

@javax.persistence.Entity
@javax.persistence.Inheritance(strategy = javax.persistence.InheritanceType.JOINED)
public class Person {
 String name;
 Long id;
 private java.util.Set<Address> address;
 public String getName() {
 return name;
 }
 public void setName(String value) {
 name = value;
 }
 @javax.persistence.Id
 public Long getId() {
 return id;
 }
 public void setId(Long value) {
 id = value;
 }
 @javax.persistence.OneToMany(mappedBy = "person")
 public java.util.Set<Address> getAddress() {
 return this.address;
 }
 public void setAddress(java.util.Set<Address> address) {
 this.address = address;
 }
}

@javax.persistence.Entity
public class Employee extends Person {
 Double salary;
 public Double getSalary() {
 return salary;
 }
 public void setSalary(java.lang.Double value) {
 salary = value;
 }
}

Now I would like to write a simple EJBQL to query for addresses named "streetName" and employees that earn more then "2000" ...

SELECT A FROM Address A WHERE (A.street=streetName) AND (A.employee.salary>2000)

==> now to my question:

As we can see, the bean path A.employee.salary is wrong and i will get a

could not resolve property: employee

but writing

SELECT A FROM Address A WHERE (A.street=streetName) AND (A.person.salary>2000)

is also wrong, because there is no salary attribute in the person entity ...

So how can I select in EJBQL using the path notation ?

Thx for any help