Wildfly 10.1.0 - Unkwnow entity (JPA)

[pacionet]

We have the following persistence.xml

<xml version="1.0" encoding="UTF-8"?>

<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">

<persistence-unit name="alertingJPA" transaction-type="JTA">

<non-jta-data-source>java:/newsletterDS</non-jta-data-source>

<class>com.Newsletter</class>

<properties>      

<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>

<property name="hibernate.hbm2ddl.auto" value="create-drop"/>

<property name="hibernate.show_sql" value="true"/>

<property name="hibernate.format_sql" value="true"/>

<property name="hibernate.use_sql_comments" value="true"/>

<property name="hibernate.generate_statistics" value="true"/>

</properties>

</persistence-unit>

<persistence>

the com.Newsletter is something like this

@Entity
@Table(name="newsletter")
@NamedQuery(name="Newsletter.findAll", query="SELECT n FROM Newsletter n")
public class Newsletter implements Serializable {
private static final long serialVersionUID = 1L;

@Id @GeneratedValue
@Column(name="ID_NEWSLETTER")
private BigInteger idNewsletter;

[...]

Application is deployed correctly but at Runtime we had this Exception

javax.ejb.EJBException: java.lang.IllegalArgumentException: Unknown entity: [Lcom.Newsletter;

CMTTxInterceptor.java:187)

Any hints?

[ctomc]

how does stractrace look like?

also what is the calling code?

As from quick look it looks like there is some array.toString() passed to entitymanager which would produce such name you see

[mayerw01]

You should check your lower_case_table_names system variable.

Depending on this value the table names may be case sensitive in MySQL.