3 Replies Latest reply on Jun 21, 2006 11:37 AM by acxjbertr

    How to acess Web service with complex parameters without ser

    tnfink
    tnfink Jun 21, 2006 3:18 AM

      Hi,

      maybe this is a silly question, but nevertheless:

      The question in the short version:

      If I want to access a Web service with a complex signature I need the jaxrpc-mapping file. If I do not use service-reference, how can I configure my code to use the jaxrpc-mapping?

      Now the longer version:

      If I try to access a Web service without using a service-reference, it will look more or less like this:

       String urlstr = "http://localhost:8080/testpurchaseservice?wsdl";
 URL url = new URL(urlstr);
 QName qname = new QName(
 "http://de.akquinet.fws.jboss.webservices.pojo/purchasews/rpcstyle",
 "PurchaseService");
 ServiceFactory factory = ServiceFactory.newInstance();
 Service service = factory.createService(url, qname);
 PurchaseServiceSEI purchaseService = (PurchaseServiceSEI) service
 .getPort(PurchaseServiceSEI.class);


      If the signature of my SEI is more complex, e.g. contains this method 

       PurchaseResult purchase(Customer customer, Product product) throws RemoteException;


      I need to map the XML parts to Java objects.

      This mapping is declared in the jaxrpc-mapping.xml file.
      But I do not specify this file in the code above, nor do I see a possibility to do this.

      I thought about using the type mapping registry. But this seems to complicated, expecially if I already have a jaxrpc-mapping.xml.

      Can anybody give me a hint to the right way of doing this?
      (I know that I can specify the mapping file in the service-ref.)

      Best regards,

      Torsten Fink

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        • 1. Re: How to acess Web service with complex parameters without
          acxjbertr
          acxjbertr Jun 21, 2006 11:06 AM (in response to tnfink)

          If your jaxrpc-mapping document is in your classpath then you can just do a getResource() on it and then pass it into the createService() method (since it is overloaded). Here is an example:

          URL wsdlLocation = new URL("http://localhost:8080/testpurchaseservice?wsdl");
URL mappingLocation = cl.getResource("jaxrpc-mapping.xml");
QName serviceName = new QName("http://de.akquinet.fws.jboss.webservices.pojo/purchasews/rpcstyle", "PurchaseService");
ServiceImpl service = (ServiceImpl) factory.createService(wsdlLocation, serviceName, mappingLocation);


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          • 2. Re: How to acess Web service with complex parameters without
            acxjbertr
            acxjbertr Jun 21, 2006 11:28 AM (in response to tnfink)

            Oops. I forgot to include a couple of lines in the example. Try this:

            ServiceFactoryImpl factory = new ServiceFactoryImpl();
ClassLoader cl = Thread.currentThread().getContextClassLoader();
URL wsdlLocation = new URL("http://localhost:8080/testpurchaseservice?wsdl");
URL mappingLocation = cl.getResource("jaxrpc-mapping.xml");
QName serviceName = new QName("http://de.akquinet.fws.jboss.webservices.pojo/purchasews/rpcstyle", "PurchaseService");
ServiceImpl service = (ServiceImpl) factory.createService(wsdlLocation, serviceName, mappingLocation);

            Also, you will need these imports as the Service from javax.xml.rpc does not have the right, overloaded method. 
            import org.jboss.ws.jaxrpc.ServiceFactoryImpl;
import org.jboss.ws.jaxrpc.ServiceImpl;


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            • 3. Re: How to acess Web service with complex parameters without
              acxjbertr
              acxjbertr Jun 21, 2006 11:37 AM (in response to tnfink)

              PS - This is mentioned in the JBossWS User Guide (http://labs.jboss.com/portal/jbossws/user-guide/en/html/clients.html) in section 5.2 ("Dynamic Invocation Interface").

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