0 Replies Latest reply on Jun 19, 2008 10:32 AM by Victor Bucutea

    listShuttle different content on each side

    Victor Bucutea Newbie

      Hi ,

      i have the following code :

      <rich:listShuttle sourceValue="#{toolBar.freeItems}"
       targetValue="#{toolBar.items}" var="items"
       sourceCaptionLabel="#{msg.adaugareProdus_titluListaProduseDisponibile}"
       targetCaptionLabel="#{msg.adaugareProdus_titluListaProduseSelectate}"
       copyAllControlLabel="#{msg.adaugareProdus_lista_CopyAllLabel}"
       converter="listShuttleconverter">
       <rich:column width="18">
       <h:graphicImage value="#{items.iconURI}"></h:graphicImage>
       </rich:column>
       <rich:column>
       <h:outputText value="#{items.label}"></h:outputText>
       </rich:column>
       <rich:column >
       <h:inputText value="#{items.cantitate}" />
       </rich:column>
       <a4j:support event="onlistchanged" reRender="items" actionListener="">
       <f:attribute name="attributeName1" value="attributeValue1" />
       </a4j:support>
       <a4j:support event="onorderchanged" reRender="items" />
       </rich:listShuttle>
      


      my problem is that i cannot figure out any way to DO NOT display the h:inputText on the left panel ( that is the selection list ) .

      If you have any ideas please share . I've been searching for quite a while a solution to this .