4 Replies Latest reply on Aug 9, 2007 12:48 PM by pmuir

    chaining jsf request

    hexxter
    hexxter Aug 8, 2007 4:12 PM

      Hello Forum,

      since my other post got no replys I try it with a shorter question:

      Is it possible to chain jsf requests an seam still works? (Call/Include another jsf page from within java code in the first jsf page)

      Thanks & regards,

      Florian

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        • 1. Re: chaining jsf request
          pmuir
          pmuir Aug 9, 2007 5:45 AM (in response to hexxter)

          Why not use facelets ui:include?

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          • 2. Re: chaining jsf request
            hexxter
            hexxter Aug 9, 2007 12:12 PM (in response to hexxter)

            Hi Pete,

            (this may be totally wrong now because I still don't really understand jsf, but)

            I'd like to change what's included dynamically. My webapp should be multidomain/multilingual in a way that I can say: includeTemplate( 'article' ) and depending on my context it would include e.g. "article_page1_en_US_top.jsf".

            I'm sorry if this is a trivial problem in jsf which I simply didn't understand but I'm trying to evaluate if I can use jsf/seam/ejb3 for my project while I haven't worked with neither of them by now.

            Regards,

            Florian

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            • 3. Re: chaining jsf request
              monkeyden
              monkeyden Aug 9, 2007 12:17 PM (in response to hexxter)

              You could use the same files, but with locale specific ResourceBundles.

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              • 4. Re: chaining jsf request
                pmuir
                pmuir Aug 9, 2007 12:48 PM (in response to hexxter)

                 

                <ui:include src="#{template.getTemplate('article')}" />


                @Name("template")
public class Template {

 public String getTemplate(String name) {
 return calculateViewId(name);
 }
}


                Obviously, you have to write calculateViewId to build your viewId on the fly.

                If it's just for i8ln of strings, then monkeyden's is the correct solution.

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