I have applicationcontext.xml where i am referring to some xml file under a folder namely config.

Here is the code snippet  of WEB-INF/applicationContext.xml:

<bean id="envConfigBuilder" class="org.apache.commons.configuration.DefaultConfigurationBuilder">

<property name="fileName">

<value>config\test_config.xml</value>

</property>

</bean>

I want to provide this folder info while running standalone.bat.

I have already tried this options but no luck.

1.standalone.bat -c C:\config\test_config.xml

2.standalone.bat -P=C:\config\test_config.xml

3.standalone.bat -Djboss.server.config.dir=C:\config

Throwing  "Cannot locate configuration source config\test_config.xml" 

Appreciate your quick help

Regards,