servlet code:
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.util.*;
public class TestingServlet extends HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
PrintWriter out = response.getWriter();
out.println("");
out.println("");
out.println("Servlet Testing");
out.println("");
out.println("");
out.println("Welcome to the Servlet Testing Center");
out.println("");
out.println("");
}
}
WEB-INF/web-xml:
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet-name>Testing</servlet-name>
<servlet-class>TestingServlet</servlet-class>
</web-app>
WEB-INF/classes/TestingServlet.class
META-INF/application.xml:
<?xml version="1.0" encoding="ISO-8859-1"?>
<display-name>Root</display-name>
<web-uri>myapp.war</web-uri>
<context-root>/myapp</context-root>
I war this up:
WEB-INF/classes/TestingServlet.class
WEB-INF/web.xml
then in an ear:
myapp.war
META-INF/application.ear
Am I totally off here? Wrhen I hit http://localhost:8080/mysql/servlet/Testing or TestingServlet I get a no context error. Any help would be appreciated.
-Christian
