Handler execution order in handler chain

[sancheski]

Hi,

I have defined three handlers in a handler chain as follows:

<?xml version="1.0" encoding="UTF-8"?>

<handler-chains xmlns="http://java.sun.com/xml/ns/javaee"
 xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:ns1="http://org.jboss.ws/jaxws/handlerscope"
 xsi:schemaLocation="http://java.sun.com/xml/ns/javaee javaee_web_services_1_2.xsd">

 <handler-chain>
 <handler>
 <handler-name>Handler 1</handler-name>
 <handler-class>
 test.HandlerOne
 </handler-class>
 </handler>
 <handler>
 <handler-name>Handler 2</handler-name>
 <handler-class>
 test.HandlerTwo
 </handler-class>
 </handler>
 <handler>
 <handler-name>Handler 3</handler-name>
 <handler-class>
 test.HandlerThree
 </handler-class>
 </handler>
 </handler-chain>

</handler-chains>

I thought that the handler execution order was going to be: handler 1, handler 2 and handler 3. But what really happened was that handlers were executed in reverse order, that is: Handler 3, handler 2, and handler 1.

My handlers implement javax.xml.ws.handler.soap.SOAPHandler and I am using jbossws 3.0.4.GA.

How can I set the handler execution order ? Are handlers in handler chain executed in reverse order as they are defined in the handler definition?


Thanks in advance,

David Sancho

[sancheski]

This is how it works, taking the descriptor file from last post:

Handlers in server side
- Server in:
1) Handler 3
2) Handler 2
3) Handler 1
- Server out:
1) Handler 1
2) Handler 2
3) Handler 3

Handlers in client side
- Client out:
1) Handler 1
2) Handler 2
3) Handler 3
- Client in:
1) Handler 3
2) Handler 2
3) Handler 1

See HandlerChainExecutor class.

Cheers,

David Sancho