Cron expression in jBPM5 gives exception

[onkarruikar]

I am using jBMP 5 and BPMN when I use following timerstart mentioned in jBPM 4 dev guide

<startEvent id="myStartEvent" >
  <timerEventDefinition>
    <timeCycle>0 0 23 ? * FRI</timeCycle>
</timerEventDefinition>
</startEvent> 

I am getting following exception:

org.drools.RuntimeDroolsException: Error parsing time string: [ 0 0 23 ? * FRI ]
    at org.drools.time.TimeUtils.parseTimeString(TimeUtils.java:132)
    at org.jbpm.workflow.instance.node.TimerNodeInstance.resolveValue(TimerNodeInstance.java:117)
    at org.jbpm.workflow.instance.node.TimerNodeInstance.createTimerInstance(TimerNodeInstance.java:75)

Please let me know how to resolve this.

[onkarruikar]

Used following rule to run the process:

import org.drools.runtime.process.ProcessContext

rule "everyDay" ruleflow-group "Hello"

    timer (cron:0 0 23 ? * FRI)   
  when
   
  then
    System.out.println(new java.util.Date());
    kcontext.getKnowledgeRuntime().startProcess("sample");
end

[salaboy21]

ok and it works?

[onkarruikar]

Yes. Register the rule and the process in knowledgebase and then fire the rule.

Please let me know if there is any other way to do this. Thanks!