Exception handling spring

[nohaapav]

Hi guys is somehow possible to get exception message from this doTry-doCatch block ?

My scenario :

which i found somewhere on camel pages but result is the same.

Thanks for any help.

Pavol

[davsclaus]

The caught exception is stored as a property on the Exchange. You can grab it using exchange.getProperty(Exchange.EXCEPTION_CAUGHT);

Chapter 5 in the Camel book covers error handling very detailed. You may find information reading the Dead Letter Channel EIP

http://fusesource.com/docs/router/2.5/eip/index.html

Or scattered information at the Camel wiki pages

http://camel.apache.org/error-handling-in-camel.html

The EXCEPTION_CAUGHT works with bean binding, so just invoke a bean in the doCatch block and put a (Exception cause) in the method signature.

[nohaapav]

Now i tried to use something like :

public class UnsupportedXmlSchema extends Exception {

public final static Logger logger = LoggerFactory.getLogger(UnsupportedXmlSchema.class);

    public void unsupportedXmlSchema(Exception ex) {

        logger.info(ex.getCause().toString());

    }

}

and works perfect so sorry for spam .. i'm a little bit overloaded seems to be ) .. and thanks of course ..

[ffang]

Hi Pavol,

Just one note,

If I understand correctly, this question is FUSE Mediation Router(Apache Camel) related only, but not FUSE Services Framework(Apache Cxf) related, would you please post such questions to correct forum category later on, it's better for track.

Thanks

Freeman