onException(Exception.class). Can't go through full exception route.

[isakoves]

I get e-mail and do some processing using web-service.

If error occurs (for example in web-service ), I need to send e-mail . But it can't go through full exception route:

onException(Exception.class)

.useOriginalMessage()

.handled(true)

.process(new Processor(){

........

prepare message to send by camel-mail

........

})

.to("direct:send_mail")

;

Mesage misses the .to("direct:send_mail") and e-mail can't send.

It can be found in log:

10:33:32,673 | WARN  | myMailEndpointIn | MailConsumer                     | 232 - org.apache.camel.camel-mail - 2.6.0 | Exchange failed, so rolling back message status: Exchange[MailMessage: ...]

Web-service settings:

Exchange is not fault but have exception.

Can it go though full exception route?

Do I need to make some settings?

[rchallapalli]

Hi,

Is this resolved??

What is your 'send_mail' consumer doing? which route is it linked to?

ravi

[isakoves]

Hello! I can't resolve it.

I tried to start new route like that:

onException(Exception.class)

.useOriginalMessage()

.handled(true)

.to("direct:exception");

from("direct:exception")

.process(....)

.to("direct:send_mail")

;

But mail can't send.

[davsclaus]

You should refer to your endpoint, so it should be  by using the ref component, to refer to the endpoint.

[isakoves]

It works good on Windows, but it does not work on Linux.