Autocomplete: i must press button twice for popup window.
I have this autocomplete component:
<table>
<tr>
<td>
<rich:autocomplete mode="ajax" autocompleteMethod="#{autocomplete.autocompleteProviders}"
minChars="0" var="s" fetchValue="#{s.realName}" id="provider-suggestion"
autofill="false"
onselectitem="autocompleteChangeProvider(event.target)" style="display: inline;"
layout="table" value="#{autocomplete.providerName}" >
<a4j:queue requestDelay="500" ignoreDupResponses="true" />
<h:column>
<h:outputText style="display:none;" value="#{s.id}"/>
<h:outputText style="display:none;" value="#{s.realName}"/>
</h:column>
<h:column>
<h:outputText value="#{s.name}" escape="false"/>
</h:column>
</rich:autocomplete>
</td>
<td>
<h:graphicImage value="/img/arrow.png" onclick="#{rich:component('provider-suggestion')}.setValue('');#{rich:component('provider-suggestion')}.showPopup();stopEvent(event);"
alt=""/>
<h:graphicImage value="/img/cancel.png"
onclick="#{rich:component('provider-suggestion')}.hidePopup();#{rich:component('provider-suggestion')}.setValue('');autocompleteChangeProvider(null);"
alt="#{messages['pages.clear']}" title="#{messages['pages.clear']}"/>
<h:inputHidden id="filter-provider-id" value="#{autocomplete.providerId}"/>
</td>
</tr>
</table>
as you can see, i don't use showButton="true", because i need another functionality, i need erase input text before show popup window.
I use JavaScript function "autocompleteChangeProvider" for extract selected id.
I use separate button(/img/cancel.png) for erase input text, as you can see this function just use Richfaces API.
And problem:
if autocomplete.providerName not null and not empty(in rich:autocomplete) and user clicks on cancel button(img/cancel.png), then after that, if user clicks on show button(/img/arrow.png) popup not showing, user must clicks twice on this button.
This problem shows if i use showButton from rich:autocomplete instead my show button.
I think i found a solution of this problem:
Autocomplete.js has this code:
var onChangeValue = function (event, value, callback) {
selectItem.call(this, event);
// value is undefined if called from AutocompleteBase onChange
var subValue = (typeof value == "undefined") ? this.__getSubValue() : value;
var oldValue = this.value;
this.value = subValue;
if ((this.options.isCachedAjax || !this.options.ajaxMode) &&
this.cache && this.cache.isCached(subValue)) {
...
} else {
if (event.keyCode == rf.KEYS.RETURN || event.type == "click") {
this.__setInputValue(subValue);
}
if (subValue.length >= this.options.minChars) {
if ((this.options.ajaxMode || this.options.lazyClientMode) && oldValue != subValue) {
callAjax.call(this, event, callback);
}
} else {
if (this.options.ajaxMode) {
clearItems.call(this);
this.__hide(event);
}
}
}
};
for show popup this must be true: oldValue != subValue, but in this part of code oldValue='' and subValue='', so oldValue != subValue is return false!
i replace this code by this:
var onChangeValue = function (event, value, callback) {
selectItem.call(this, event);
// value is undefined if called from AutocompleteBase onChange
var subValue = (typeof value == "undefined") ? this.__getSubValue() : value;
var oldValue = this.value;
this.value = subValue;
if ((this.options.isCachedAjax || !this.options.ajaxMode) &&
this.cache && this.cache.isCached(subValue)) {
...
} else {
if (event.keyCode == rf.KEYS.RETURN || event.type == "click") {
this.__setInputValue(subValue);
}
if (subValue.length >= this.options.minChars) {
if ((this.options.ajaxMode || this.options.lazyClientMode) && (oldValue != subValue || (oldValue === '' && subValue === ''))) {
callAjax.call(this, event, callback);
}
} else {
if (this.options.ajaxMode) {
clearItems.call(this);
this.__hide(event);
}
}
}
};
so, than oldValue='' and subValue=='' callAjax.call will be called and popup will be showing.
Is this right resolve?
